NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post
NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post have released the notification, for helpful information like Stipendiary Trainee with the job vacancies of 391 Post. The job vacancies announcement for this job has been located in the place of Kaiga Site . For this job Recruitment, the candidate should have a minimum education eligibility criteria like 12th std/ ITI/ Diploma/ Degree to their current job. Eligible candidates can apply for this job vacancy of 391,Stipendiary Trainee Post.
NPCIL Job Recruitment 2025 releases the official notification from the starting date of 12/03/2025 and the closing date of 01/04/2025 . For the applying NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post procedure, the candidate needs to fill out their respective application either online or offline as per the notification released by NPCIL . Below we have explained briefly explained about the NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post like education details, age limits, how to apply, closing date of NPCIL Job Recruitment 2025 .
NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post Short Details:-
Organization | NPCIL – Nuclear Power Corporation Of India Limited |
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Category | Central Govt Jobs |
Job type | permanent appointment |
Vacancy | 391, Stipendiary Trainee Placement |
location of job | Kaiga Site |
Required Education qualification | 12th std/ ITI/ Diploma/ Degree |
Opening date for a given job | 12/03/2025 |
Closing date for a given job | 01/04/2025 |
NPCIL Recruitment vacancy 2025 :-
According to the post of NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post recruits 391 candidates to select. All candidates have to be requested to check the current job openings of NPCIL Job Recruitment 2025 before applying to this job recruitment.
- NPCIL Job Recruitment 2025 released recruitment posts of 391 in different types.
- also, Study the Notification given NPCIL pdf
Post Name:-
There are 8 types of jobs given in the NPCIL . For a brief explanation we have given below:-
Scientific Assistant – B – 45 |
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Category – I: Stipendiary Trainee/ Scientific Assistant (ST/SA) – 82 |
Category – II: Stipendiary Trainee/ Technician (ST/Technician) – 226 |
Assistant Grade – 1 (HR) – 22 |
Assistant Grade – 1 (F&A) – 04 |
Assistant Grade – 1 (C&MM) – 10 |
Nurse A – 01 |
Technician/C (X-Ray Technician) – 01 |
- also, Study the Notification given NPCIL pdf
Education qualification details for NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post:-
Applying for NPCIL jobs, the candidate should have some qualification with a minimum education Qualification of, 12th std/ ITI/ Diploma/ Degree . For a brief explanation of NPCIL Job Recruitment 2025 , we have tabled below:-
Post name | qualification |
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Scientific Assistant – B | Diploma in Engineering or BSc |
Category – I: Stipendiary Trainee/ Scientific Assistant | Diploma in Engineering |
Category – II: Stipendiary Trainee/ Technician | ITI |
Assistant Grade – 1 (HR) | 12th std in Science Stream |
Assistant Grade – 1 (F&A) | UG Degree |
Assistant Grade – 1 (C&MM) | UG Degree |
Nurse – A | 12th std + Nursing Diploma/ Degree |
Technician/C (X-Ray Technician) | 12th std + 1-year Radiography Certificate |
Note:-
- also, Study the Notification given NPCIL pdf
Age limit for NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post:-
post name | maximum age limit |
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Scientific Assistant – B | 30 age |
Category – I: Stipendiary Trainee/ Scientific Assistant | 25 age |
Category – II: Stipendiary Trainee/ Technician | 24 age |
Assistant Grade – 1 (HR) | 28 age |
Assistant Grade – 1 (F&A) | |
Assistant Grade – 1 (C&MM) | |
Nurse – A | 30 age |
Technician/C (X-Ray Technician) | 25 age |
Salary for NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post:-
For the NPCIL , Salary details look the view on it which was given below
post title | pay per month |
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Scientific Assistant – B | Rs.54,162/- Per Month |
Category – I: Stipendiary Trainee/ Scientific Assistant (ST/SA) | Rs.54,162/- Per Month |
Category – II: Stipendiary Trainee/ Technician (ST/Technician) | Rs.33,201/- Per Month |
Assistant Grade – 1 (HR) | Rs.39,015/- Per Month |
Assistant Grade – 1 (F&A) | Rs.39,015/- Per Month |
Assistant Grade – 1 (C&MM) | Rs.39,015/- Per Month |
Nurse – A | Rs.68,697/- Per Month |
Technician/C (X-Ray Technician) | Rs.39,015/- Per Month |
Process mode:-
NPCIL requires the application form, to apply the Stipendiary Trainee posts by Online.
Application fees:-
category | fees |
---|---|
All Categories | Rs.150/- |
ST/SC/Ex-s/PWD Categories | no fees |
How to select for the post NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post:-
NPCIL , candidate can be selected by the following method:-
- Online Test
- Skill Test
Step by Step apply for NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post:
- For applying, the candidate should open the official website https://www.npcilcareers.co.in/
- Then the candidate would like to find the respective NPCIL Job Recruitment 2025 on the particular page.
- Click the Stipendiary Trainee official notification that has to be downloaded and read it carefully.
- Fill in the particular details without any mistakes.
- Once the application is filled out, check the correct data one or more times. which have been asked for the post of Stipendiary Trainee .
- Make the payment if it is required otherwise skip this step.
- finally, submit your application.
NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post Important Dates to Reminder:-
NPCIL Job Recruitment 2025 official notification available on (12/03/2025 )
Last date: 01/04/2025
The official notification for NPCIL Job Recruitment 2025 – 391, Stipendiary Trainee Post:-
Official Notification Pdf |
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Official Application Form |
FAQ – NPCIL Job Recruitment 2025
1. How many vacancies are available?
There are 391 vacancies.
2. What is the job location?
Kaiga Site.
3. What is the required qualification?
12th std/ ITI/ Diploma/ Degree (varies by post).
4. What is the age limit?
24 to 30 years (varies by post).
5. What is the salary?
Rs.33,201/- to Rs.68,697/- per month.